1-甲基-1,4,7,10-四氮杂环十二烷

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| C=9 | H=22 | N=4
| Appearance = 白色固体它也可由1,4,7,10-四氮杂环十二烷先后和乙二醛、碘甲烷和水合肼反应得到。它可以和高氯酸镍在乙醇中反应，得到黄色的Ni(C9H22N4)2。

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